Sažetak
In this paper, we consider the problem about finding out perfect powers in an alternating sum of consecutive cubes. More precisely, we completely solve the Diophantine equation (x+1) 3 - (x+2) 3 + ∙∙∙ - (x + 2d) 3 + (x + 2d + 1) 3 = z p, where p is prime and x,d,z are integers with 1 ≤ d ≤ 50.